邻苯二甲酸氢钾式量较大，所以物质的量相同时，其称量误差较小。 A、正确 B、错误 - 查题网

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成人高等教育 / 无机化学与分析化学

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邻苯二甲酸氢钾式量较大，所以物质的量相同时，其称量误差较小。

A、正确
B、错误

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无机化学与分析化学

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