22[分析题]
#include<iostream.h> void fun10(int *a[],int m,int n) {     int i,j;     for(i=0;i<m;i )        a[i]=new int [n];     for(i=0;i<m;i )        for(j=0;j<n;j )            a[i][j]=(i 1)*(j 1); } void main() {int m1=2,n1=2; int **b=new int *[m1]; fun10(b,m1,n1); for(int i=0;i<m1;i ){     for(int j=0;j<n1;j )        cout<<b[i][j]<<’ ’;     cout<<endl; }    }