1[分析题]
#include<iomanip.h> const int M=20; void main() {     int c2,c3,c5;     c2=c3=c5=0;     for(int i=1;i<=M;i )        {            if(i%2==0) c2 ;            if(i%3==0) c3 ;            if(i%5==0) c5 ;        }    cout<<c2<<’ ‘<<c3<<’ ‘<<c5<<endl; }